i have added a break point at a line but while debugging it gives me an error saying that the line can not be executed. the whole program works fine. please see the attached screenshot.
thank you
Optimizer put that variable into register.
If you look it in debugger with Show disassembly you see it in eax.
EDIT:
75:
76: top = -1;
00401160 or dword ptr [top],-FF
77: flag = 0;
78:
79: for (i = 0; expression[i] != '\0'; i++)
00401164 xor ebx,ebx
00401166 jmp 004011D5
{
if (isbracket(expression[i]))
00401168 movzx eax,byte ptr [expression+ebx]
...
89: {
90: flag = 1;
91: break;
004011CD mov eax,00000001
004011D2 jmp 004011DE
92: }
...
Without optimization or volatile int flag you can step to that line too.
i am not getting what you are saying. Can you explain it in more detail? Thank you