Print Page - Pointer as return-value of a function

Title: Pointer as return-value of a function
Post by: scy on November 04, 2015, 03:05:17 PM

hey guys,

i am trying to write a function where i convert a string of numbers to their ASCII-equals

i know that a function can only have 1 return value which is why i want/need to have a pointer as a return value to return the whole string.

i know that i need a pointer but i have no clue how to write the function.

Code:

Code Select

int *stoi(char str[]) {
	int z;
	int g = 0;

	for (z = 0; str[z] != '\0'; z++) {
		g = ctoi(str[z]);
		str[z] = g;
	}

	return str;
}

this is the ctoi function:

Code Select

int ctoi(char c) {
	int i = 0;

	i = c - '0';

	return i;
}

this is the code i have for the function.
i want to call the function like this:

Code Select

char *str = "-211";
	int *x;
	x = stoi(str);
	printf("\n%i \n", *x);
	return EXIT_SUCCESS;

and as you see i want to output the string into the console, but it just stays empty.

i am using eclipse-c++ on ubuntu linux

Title: Re: Pointer as return-value of a function
Post by: Bitbeisser on November 05, 2015, 12:32:37 AM

Quote from: scy on November 04, 2015, 03:05:17 PM
i am using eclipse-c++ on ubuntu linux

Well, this forum is for Pelle's C, which only runs on Windows ;-)

And we usually don't do the homework for other either.

I am a bit short on time right now (just stopped by to check for spammers to zap), I will get back to you with some hints later if no one else is biting in the meantime ... ;)

Ralf

Pelles C forum

C language => Beginner questions => Topic started by: scy on November 04, 2015, 03:05:17 PM