Q. checking single character in string (char array)

[darrenf]

Hi,

Wonder if someone can help here.

I am trying to set up the condition....   if char

• in stringArray is ',' then do something
  
  a sample code is below.
  
  Peles C gives me the error....
  
  >  C:/progs> cc /c chardebug.c
  >  charDebug.c
  >  charDebug.c(29): error #2168: Operands of '==' have incompatible types 'char' and 'char *'.
  
  some simple code in context of how I want to use it (solve this, solve problem) is....
  
  ------------ charDebug.c -----------------
  
  #include <stdlib.h>
  #include <stdio.h>
  #include <string.h>
  
  
  int countChar(char *);
  
  
  int main(void)
  {
    char lstr[255];
  
    sprintf(lstr,"10,45,67,89,ABC");
  
    printf("\n\n the string has %d data items", countChar(lstr));
  
  }
  
  
  int countChar(char lstr[])
  {
       int  fByte, wpos, numItems;
  
       numItems=0;
       fByte = strlen(lstr);
           wpos = 1;
           while (wpos<fByte)
            {
             if(lstr[wpos]==" ")
               numItems++;
            wpos++;
            }
  
  return(numItems);
  }
  
  ----------------------------------------------------
  
  thanks for your help.   
  
  
  
  
  

[AlexN]

>  charDebug.c(29): error #2168: Operands of '==' have incompatible types 'char' and 'char *'.

Try this:

Code Select Expand

if(lstr[wpos]==' ')
If you use " ", you define a string. if you use ' ', you define a charater.

[darrenf]

thanks Alex,  sitting here now wondering why I had not picked this up.
Your help is appreciated.