wrong operator

[czerny]

Code: [Select]

printf("%u\n", 2^31);
Why is the compiler not complaining about this?

[JohnF]

I don't think the compiler is checking.

printf("%d\n", 2^44);

However, it does with this.

unsigned long long ll = 9;
printf("%d\n", ll);

John

[czerny]

Have you seen the output?

Code: [Select]

#define m1 2^32
printf("m1 : %u\n", m1);  // 34

#define m2 2^31
printf("m2 : %u\n", m2);  // 29

printf("m3 : %u\n", 2^44);  // 46


[JohnF]

I have. One assumes that without an actual type it is not checked.

And it appears that ^ is not doing the right thing.

John
 

[aardvajk]

It really is a sad sight to see two people who've presumably been using C for years not know that ^ is XOR.
pow is in math.h

[JohnF]

It really is a sad sight to see two people who've presumably been using C for years not know that ^ is XOR.
pow is in math.h

You're right!

John

[czerny]

It really is a sad sight to see two people who've presumably been using C for years not know that ^ is XOR.
pow is in math.h

You're right!

John

Hihi, thats funny! Everyone is a beginner, somehow!
Hey aardvajk, don't feel sad, laugh with us!