Is there a way to declare a struct pointer and assign values in one line?

[Gary Willoughby]

Is there a way to declare a struct pointer and assign values in one line?

like this, maybe?

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struct RECT *a = {10, 20, 30, 40};
this errors, btw.

[JohnF]

Is there a way to declare a struct pointer and assign values in one line?

like this, maybe?

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struct RECT *a = {10, 20, 30, 40};
this errors, btw.

That will not do because there is no space allocated for the struct, all you have is space allocated for a pointer to a struct.

So the answer to your question I think is no.

John

[DMac]

You can do it in two lines, no less.

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typedef struct tagRECT { long l; long t; long r; long b; } RECT;
RECT rc = {1,2,3,4};
Now if you are using the windows api, RECT is already declared, so in your method doing the following:

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VOID MyMethod(void){
     RECT rcTxt = { 0, 0, 10, 5 };

Declares an instance of and initialize your struct.

[JohnF]

He did ask about a struct pointer.

John

[Stefan Pendl]

You can only initialize a struct, if you need a pointer to a struct as an argument for a function you usually use &struct, if I am not mistaken.

So one would use the following:

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struct RECT a = {10, 20, 30, 40};
myfun(&a);

[frankie]

You have to specify that you want to assign the address of the defined struct, and you have to specify that the initialization data is the struct you need with a cast.
Look the following example:

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typedef struct {int a; int b; int c;} tst;
tst *r = &((tst){1, 2, 3});
tst *s = &((tst){4, 5, 6});
.... etc.
In your case:

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struct RECT *a = &((struct RECT ){10, 20, 30, 40});